∵正三棱柱ABC-A1B1C1 中,AB=2,AA1=1,D是BC的中点,∴AD⊥CD,CC1⊥CD,CC1⊥AC,∴AC1= 22+12 = 5 ,AD= 22?12 = 3 ,C1D= 1+1 = 2 ,∴AD⊥C1D,∴∠C1DC是二面角C1-AD-C的平面角,∵tan∠C1DC= C1C DC =1,∴∠C1DC=45°,∴二面角C1-AD-C的大小为45°.